Home Forums Hunting & Shooting Hunter's Campfire More Caveman math...

If you printed it you could mostly verify it with a compass but it's not stated.

A four sided square with obvious radii...

Dude... ease back on the over-thinking.

Next thing you will say is that Big Mike is a gal... unless... I prove otherwise.

Which I ain't.

IF you assume what appears to be obvious.

How in the fugg is a radius that is based on a perfect square... somehow NOT A RADIUS?

Seriously...

Good Lord.

Poindexter.

I apologize. This is a game that isn't intended to be pure math. Math is a pure science that doesn't allow for guesses and that's not the intent of a game. I got a little carried away with the math part and left out the game part.

Cool RC... No apology needed.

I treat math... like I treat science, like medicine, like the law... engineering and architecture... hunting and fishing...

Nothing is fact... just practical "Practice".

Only a dog's love is Fact...

To me.

I sent the original problem to my friend, a PhD Optical Physicist that worked on the James Webb Space Telescope. He sent me back:

8-2π + π-2+ π-2= 4

BTW, π = Pi, if it doesn't show well in our text.
And on international Pi Day at that.
Just like me, he didn't "see" the caveman-level solution. Didn't keep him from the answer though.

Rex

I think you transposed the formula a bit. I believe it should be:

8-2n - n-2 - n-2 = 4

25 % of total area of the square......4 sq whatevers

Longbob
What you typed as "n" is supposed to be Pi. It didn't endure the font transposition as well as I'd have liked when copy/pasted.

As I presented it (copy/pasted from my friend's reply to me, whose name is also Bob, BTW) it = 1.7168 + 1.1416 + 1.1416 = 4.0000
As you're suggesting it = 1.7168 - 1.1416 - 1.1416 = (-0.5664)

One thing I've learnt is not to mess with Bob, when it comes to cypherin'

Cheers,
Rex

I don't do hyperbola or parabola.

You are right. I was driving, figuring, and typing at that same time.

Being able to do hard math like that is very impressive to me. I can not.

I just work out stuff like this in "my head"... visually folding paper (in this case)...

Projecting lines and angles in other problems... kinda thing.

Mostly it is just a silly hobby... but it kinda helps me think out other stuff sometimes.

Two part problem...

What is the Area?

What is the length of AB?

Fitty%/2

area = 60

AB = sq root of 5, whatever that is.

60 and 5.

Looking at it again: 60 and 2.5 x square root of 3 which is 1.732 = 4.33

Area is 60 and length of AB is sqrt of 20.

Let’s see if I can explain my logic..

Draw a line from A to D.
Call the point where the that line intersects line BC point E
That line bisects line BC which makes BE = 2.5 and also makes line AE = 5.
If you rotate the triangle CDE counter clockwise you will see the two triangles are congruent and then form a 10 x 6 rectangle.
The area is 10 x 6 or 60

Now to solve for AB:
The hypotenuse of triangle ABE is 5 (half of ten)
Side BE is 2.5
That makes triangle ABE a 30/60 right triangle, where the sides are 1, 2 and square root of 3 (1.732)
Side AB is 2.5 x 1.732 = 4.33