Serious question .. maybe I'm the only one who doesn't know the answer.
Lets say the burrito carton says serving size is one burrito and the instructions are to nuke it for 1 minute, flip it over, and nuke it for another minute. How much do I adjust cooking time if I want to 2 burritos at once? Is there some magic formula? I didn't fail home ec 'cause I never took it in the first place.
Keep adding 30 seconds and testing with your finger. You’ll eventually get to the point where part of it is still frozen and right beside it it will melt the roof of your mouth.
Easy peasy, you can do it. Microwave magnetron tube emitting 1,120 watts at 1,750 Mhz. Take the specific gravity of the burrito multiplied by the mass in cu cm. Obtain the cube root of the microwave power minus the .7 power factor and divide that into the burrito mass/weight ratio (corrected to 15.556 centigrade), correct for ambient air temp and divide by 60 min. You should be within 1 second of piping hot without excessive cheese melt.
I'm not that smart actually, Mathman showed me how to do it.
Easy peasy, you can do it. Microwave magnetron tube emitting 1,120 watts at 1,750 Mhz. Take the specific gravity of the burrito multiplied by the mass in cu cm. Obtain the cube root of the microwave power minus the .7 power factor and divide that into the burrito mass/weight ratio (corrected to 15.556 centigrade), correct for ambient air temp and divide by 60 min. You should be within 1 second of piping hot without excessive cheese melt.
I'm not that smart actually, Mathman showed me how to do it.
That is an absolutely perfect response! The only thing that I would add is that you should have strongly emphasized the AMBIENT temperature to ensure that the reader would not inadvertently correct for the plain old surrounding air temperature rather than the ambient temperature.
Easy peasy, you can do it. Microwave magnetron tube emitting 1,120 watts at 1,750 Mhz. Take the specific gravity of the burrito multiplied by the mass in cu cm. Obtain the cube root of the microwave power minus the .7 power factor and divide that into the burrito mass/weight ratio (corrected to 15.556 centigrade), correct for ambient air temp and divide by 60 min. You should be within 1 second of piping hot without excessive cheese melt.
I'm not that smart actually, Mathman showed me how to do it.
That is an absolutely perfect response! The only thing that I would add is that you should have strongly emphasized the AMBIENT temperature to ensure that the reader would not inadvertently correct for the plain old surrounding air temperature rather than the ambient temperature.
Not to mention relative humidity and altitude.
Xavier Becerra head of Health & Human Services commenting recently on un vaxxed immigrantes: "The science is not settled on the ambient temperature of burritos".
