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50:1 on the newer saws.


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Originally Posted by Tarkio
OK. I can't do proper chemical nomenclature here but I will try to give a very simplified example of the problem.

You are going to react H2 gas with O2 to create H2O, water.

If you have 7 mols of H2 and 11 mols of O2, calculate the largest amount of H2O that could be produced. Answer to the nearest .1 mol

7 mols H2 plus 3.5 mols O2 yields 7 mols H2O


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Originally Posted by Jim_Conrad
Originally Posted by FatCity67
Worried about posting inane subjects in this place?

That in itself.

I have a Masters Degree....in Inanity

And you didn't have to take out student loans


"Maybe we're all happy."

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Originally Posted by Tarkio
OK. I can't do proper chemical nomenclature here but I will try to give a very simplified example of the problem.

You are going to react H2 gas with O2 to create H2O, water.

If you have 7 mols of H2 and 11 mols of O2, calculate the largest amount of H2O that could be produced. Answer to the nearest .1 mol

I don't knows much abouts making water... 'cept...

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If you are not actively engaging EVERY enemy you encounter... you are allowing another to fight for you... and that is cowardice... plain and simple.



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This just proves nothing is "simple" with Chemistry.

IC B2

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Originally Posted by CashisKing
Originally Posted by Tarkio
OK. I can't do proper chemical nomenclature here but I will try to give a very simplified example of the problem.

You are going to react H2 gas with O2 to create H2O, water.

If you have 7 mols of H2 and 11 mols of O2, calculate the largest amount of H2O that could be produced. Answer to the nearest .1 mol

I don't knows much abouts making water... 'cept...

[Linked Image from i.postimg.cc]

Just picked up a bottled and bonded by them, solid sipper

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whew-- Good thing it wasn't at what temp. must a phenyl- ketone condensation with dietheylamine occur to make meth.


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Originally Posted by kenster99
50:1 on the newer saws.


Avogadro says the answer is 6.023 x ten to the 23rd power (I can't do superscripts on this forum!).


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