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OK, here's the formula in Speer's reloading manual for determining wind drift.

DRIFT r = Vw X [TOF - R/Vm]

DRIFT r, the r = range. Vw is the velocity of the wind. TOF is the Time Of Flight, or exposure time. R is again Range, which is divided by Vm, or muzzle velocity.

TOF is in fractions of a second, to a given Range in feet, and as I said Vw is wind velocity in feet per second. Vm is the muzzle velocity in FPS.

Your result will be in feet...divide by 12 and you'll get the answer in inches or fractions of inches.


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The best explaination of bullet drift is in "Rifle accuracy facts".
The spin stabilisation turns the bullet so that the "wind' is blowing straight back (zero angle of attact). Part of the drag is now down range and causes the drift. Since ballistic coefficent is defined as velocity lost, drift depends on the velocity lost. No Virginia the wind doesn't blow against the side of the bullet.
Take Care!


So, you're saying the drift of the bullet would be the same in a 30 MPH wind as it would be in a 5 MPH wind (full value?) Any fool knows that's not true.

The definition of ballistic coefficient is the weight of the bullet in pounds divided by the square of its caliber in inches, and by a factor related to the shape of the bullet (which I don't know...gotta look it up.) It's also meaured at different velocities, but basically, the static BC of a bullet gives you all the information you need, in most cases.


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You know that is not what I said (speaking of fools). A bullet would turn furthur into a higher speed wind and more of the drag would be down wind. If you didn't like the 22 bullet droping try this. Please read it before you reply.
Consuder an aeroplane flying in a gross wind. The pilot steers into the wind to maintain course. In this case the downwind drag that the bullet would see is balanced out by the thrust of the prop.
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Most bullets don't have pilots, and most airplanes without pilot action would be blown grossly off course. And bullets, unlike airplanes, don't have the ability to speed up in the face of the wind. There's simply no comparison between airplanes and bullets.

I can't see how you fail to grasp the simple concept that wind will move a bullet. For a bullet to do as you say, it would have to yaw, and wouldn't enter the target cleanly, but keyhole.

Can't see how, when a formula is offered from a reputable source, you can't accept the facts.


Last edited by Gene L; 09/28/06.

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I was trying to help you grasp the concepr of resolving vectors into two forces.
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I was trying to help you grasp the concept of resolving vectors into two forces.
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Sorry, hawkins. You're intelligent and probaby a good mathematician, but "two vectors" doesn't seem to apply to bullets.

In fact, I don't think (as a poor mathamatician, that any object can go in two directions at the same time.


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Hi guys, I have a Sako .270 that shoots tite groups inch and a half high at 100 yards with winchester 150gr. ammo. This year I am going to be hunting deer from a treestand 20 feet up and shooting out to possibly 300 yards. What I am wondering is how do you think the 20 foot elevation will affect my bullets point of impact at that range whether it will be lower than on the ground or the same? I would just like to be prepared when a 12 pointer comes out at 300 so I know how to aim differently. Chris.


You're overthinking...put the crosshairs on it, and squeeze it off.

If you were 40ft up a tree with a bow and a deer at 30 yards, you might have to adjust. 20ft up and a .270 is no problem.


War Damn Eagle!


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