Originally Posted by Idaho_Shooter
Originally Posted by ElkSlayer91
Originally Posted by BALLISTIK
1/(2x2x2x2) for the odds of all roosters, 1/(2x2x2) for 3 roosters or hens, etc. It's been quite a while since I took a course that covered statistics/probability material, but I think it's right. 1/16 of a chance for all roosters or hens.

1/16 - 6.25 - 1 rooster
2/16 - 12.5% - 2 roosters
3/16 - 18.75% - 3 roosters
4/16 - 25% - 4 roosters

Elkslayer, something is wrong here.

You have it twice as likely to get four of the same sex as to get an even split.

And you have the odds of getting three females at 15/16 while odds of getting three males is 3/16.

Ballistik had it right. You have to get the common denominator first. 2x2x2x2, then you factor it out. There are two possibilities for each egg. You're only accounting for one with the eight denominator.

if you take your 4H x 4T = 16, you get the same correct common denominator you need to run the formula correctly.


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