Originally Posted by BALLISTIK
1/(2x2x2x2) for the odds of all roosters, 1/(2x2x2) for 3 roosters or hens, etc. It's been quite a while since I took a course that covered statistics/probability material, but I think it's right. 1/16 of a chance for all roosters or hens.

I’m going with this until mathman sees this! 🤣

1/2 x 1/2 x 1/2 x 1/2 for all four to be roosters.

Last edited by ironbender; 04/15/21. Reason: Friggen autocorrect
If you take the time it takes, it takes less time.
--Pat Parelli

American by birth; Alaskan by choice.
--ironbender