The probability of 1 hen is the same as 1 rooster. If either of those happen, regardless of the arrangement, the other 3 are the other sex. Can't see how anyone can argue otherwise, unless I'm missing something.
That's good for when on a given egg the probability of a rooster is the same as the probability of a hen. If it's not 50/50 then while there are the same number of ways to get one rooster as there are for one hen in four tries, but the probability is skewed.
