I'm curious where you come up with the greater bearing surface on the 45, looking at bullet designs on the Mountain Molds website I come up with less bearing surface for the.
I simply calculated the circumference of the .45 cal bullet compared to circumference of the 44 mag (.429 cal). Comparing the circumferences shows the .45 cal bullet's circumference is 15% greater than the .429 cal bullet. Given the same length bullets, or say the same length of contact in the bore, the .45 cal bullet will have 15% more bullet exterior contacting the bore than the .429 cal 44 mag.
Originally Posted by 458 Lott
For the same weight bullet the 45 is shorter and assuming one uses the same nose length i.e. forward of the canalure on an ogival wadcutter i.e. lfn shape the 44 has a longer base and longer driving bands than the 45 for a given weight. In the case of a 250 gr with a .35" nose and 75% meplat the 44 had roughly 10% more bearing surface due to the longer base bands for a single lube groove bullet.
What you just posted above shows my ignorance regarding the length of 45 colt bullets vs. the lengths of various 44 magnum bullets. I have learned something and stand corrected.
Originally Posted by 458 Lott
If you want to have a closer comparison it's better to use a 10% heavier bullet and at that point the 45 has 10% more weight, base dia, wound channel and due to lower operating pressure about 100 fps slower all while burning the same amount of powder than the 44.
Once again you have educated me. Thank you.
Originally Posted by 458 Lott
Everyone has their preferences, but the math doesn't lie.
